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Cylinder





Question


Q1. Radius and height of right circular cylinder is increased by 10% and 20% respectively. find percentage increase in volume of cylinder .

(a) 30% (b) 20% (c) 45.2% (d) 48.2%

Solution.
(c) 45.2%
Solution

Q2. Curved surface area of a right circular cylinder is 1100 cm2.If the circumference of the base is 110 cm, find the height of the cylinder .

(a) 12 cm (b) 25 cm (c) 10 cm (d) 20 cm

Solution.
2πrh = 1100
Circumference (2πr) = 110
110(h) = 1100
h = 10
Solution

Q3. For the same height and base radius, volume of cylinder will __________ times, the volume of cone.

(a) 2 (b) 1 (c) 4 (d) 3

Solution.
(d) 3
Volume of cylinder = πr2h
Volume of cone = 1/3 πr2h
Solution

Q4. If the radius of the cylinder becomes 2 times then the new volume of the cylinder will be ________ times.

Solution.
4
Solution

Q5. Curved surface area of a right circular cylinder is 44 cm2 its circumference is 44 cm find the height.

Solution.
1
Solution

Q6. A student has rectangular sheet of dimensions 14 cm x 20 cm. He want to develop a minimum volume cylinder, find its height.

Solution.
20 cm
Solution

Q7. Volume of cylinder is V1, surface area is A and radius of base is r so find the volume ?

Solution.
A = 2πrh, V1 = πr2h

A/ V1 = 2πrh/πr2h

V1 = Ar/2
Solution

Q8. Height of cylinder is doubled then the new volume will be .

(a) same (b) triple (c) double (d) none of these

Solution.
(c) double
volume is πr2h
new volume = πr2(2h) = 2πr2
Solution

Q9. Height of cylinder is (1/4)th of the original height and radius become doubled, then the volume of new cylinder will be.

(a) same (b) triple (c) double (d) none of these

Solution.
(a) same
original volume = πr2h
new volume will be = π(2r)2 x h/4
= πr2h
Solution

Q10. A student has rectangular sheet of dimensions 22 cm x 30 cm . He want to make a cylinder in such a way so that volume is minimum. Then height of the cylinder will be

(a) 22 cm (b) 30 cm (c) 11 cm (d) 15 cm

Solution.
(b) 30 cm
Volume will be minimum , when rectangular sheet is rolled along minimum length.
Solution