Q1.
When 335 is added to 5A7 the result is 8B2 is divisible by 3. What is the largest possible value of A.
(a)8 (b)2 (c)1 (d)4
Solution.
5A7
335
8B2
A = 1,2,3,4,5,and
B = 5,6,7,8,9
8B2 is exactly divisible by 3.
8 + B + 2 = multiple of 3
B = 5 or 8 , A = 1 or 4
Solution
Q2.
The product of two numbers is 4107. if the H.C.F of the numbers is 37 the greater number is.
(a)185 (b)111 (c)107 (d)101
Solution.
LCM = Product of two numbers/HCF
4107/37 = 111
Obviously, numbers are 111 and 37 which satisfy the given condition.
Hence,the greater number = 111
Note :1stnumber x 2nd= LCM x HCF
Solution
Q3.
On simplification 3034 - (1002/20.04)is equal to :.
(a)3029 (b)2984 (c)2993 (d)2543
Solution.
3034 - (1002/20.04)
= 3034 - (1002/2004) x 100
= 3034 - 50
=2984
Solution
Q4.
The value of(256)0.16 x (256)0.09 is :.
(a)256.25 (b)64 (c)16 (d)4
Solution.
(256)16/100 x (256)9/100
= (256)25/100
= (256)1/4
= (44)1/4
=(4)4 x 1/4 = 4
Solution
Q5.
The average of 30 results is 20 and the average of other 20 results is 30. what is the average of all the results.
(a)24 (b)48 (c)25 (d)50
Solution.
Required average
= (20 x 30 + 20 x 30)/(30 x 20)
= 600 + 600/50
= 1200/50 = 24
Solution
Q6.
If x : y = 3 : 1 then x3 - y3 : x3 + y3 = ?.
(a)13:14 (b)14:13 (c)10:11 (d)11:10
Solution.
x/y = 3/1 = x3/y3 = 27/1
x3 - y3/x3 + y3
= (27 - 1)/(27 + 1)
= 26/28 = 13/14
= 13:14
Solution
Q7.
What is 20% of 25% of 300?
(a)150 (b)60 (c)45 (d)15
Solution.
20% of 25% of 300
20/100 x 25/100 x 300
1/5 x 1/4 x 300 = 15
Solution
Q8.
A man bought an old typewriter for Rs.1200 and spend Rs.200 on its repair. He sold it for Rs.1680 his profit percent is
.
(a)20% (b)10% (c)8% (d)16%
Solution.
Total cost of typewriter
= Rs(1200+200) = Rs.1400
S.P = Rs.1680
Profit = Rs(1680 - 1400)
= Rs.280
Profit% =
280/1400 x 100 = 20%
Solution
Q9.
The equivalent single discounts for two successive discounts of 15% and 10% is.
(a)25% (b)20% (c)23.5% (d)20.5%
Solution.
Equivalent discount
= (15 + 10 - 15 x 10/100)%
= 23.5%
Solution
Q10.
What annual instalment will discharge a debt of Rs.6450 due in 4 years at 5% simple interest?
(a)Rs1500 (b)Rs1835 (c)Rs1935 (d)Rs1950
Solution.
Equal instalment
= 6450 x 200/4[200 +(4 - 1)x 5]
= 6450 x 200/4(215)
= 6450 x 50/215
= Rs 1500
Solution
Q11.
A alone can complete a work in 12 days. A and B together can complete it in 8 days.How long will B alone take to complete the work.
(a)24 days (b)18 days (c)16 days (d)20 days
Solution.
A's 1 day's work = 1/12
(A +B)'s 1 day's work = 1/8
B's 1 day's work
= 1/8 - 1/12
3 - 2/24 = 1/24
B alone can do the work in 24 days.
Solution
Q12.
12 Pumps working 6 hours a days can empty a completely filled reservoir in 15 days.How many such pumps working a hours a day will empty
the same reservoir in 12 days?.
(a)15 (b)9 (c)10 (d)12
Solution.
Hours/day = 6,9
Days = 15,12
Pumps = 12,x
Let x be number of pumps.
9:6::12:x = 12:15::12:x
9 x 12 x (x) =
6 x 12 x 15
x = (6 x 12 x 15)/(9 x 12) = 10
Solution
Q13.
A car goes 10 metres in a second.Find its speed in km/hour .
(a)40 (b)32 (c)48 (d)36
Solution.
Speed of car = 10m/sec
Required speed in kmph
(10 x 18)/5
= 36km/hr.
Solution
Q14.
A man can row 15km/hr downstream and 9 km/hr upstream. The speed of the boat in still water is.
(a)8 km/hr (b)10 km/hr (c)15 km/hr (d)12 km/hr
Solution.
Speed of boat in still water
= 1/2(Rate downstream + Rate upstream)
= 1/2(15 + 9)
= 1/2 x 24 = 12 km/hr.
Solution
Q15.
If 3x+3 + 7 = 250, then x is equal to.
(a)5 (b)3 (c)2 (d)1
Solution.
3x+3 + 7 = 250
3x+3 = 243
3x+3 = 35
x+3 = 5
x = 2
Solution
