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Unit 2

Q1. The numerator of a fraction is increased by 20% and its denominator is decreased by 10% the value of fraction becomes 3/2. find the original fraction .

(a) 4/7 (b) 9/8 (c) 2/3 (d) 1/3

Solution.
(b) 9/8
Let original fraction is x/y

120% of x/ 90% of y
=
3/ 2


12x/ 9y
=
3/ 2


x/ y
=
3 x 9/ 12 x 2
Solution

Q2. How many numbers upto 840 are divisible by 4,3 and 6 together .

(a) 76 (b) 48 (c) 60 (d) 70

Solution.
the the LCM of 4,3 and 6 = 12

840 ÷ 12 = 70
Solution

Q3. Find the unit's place digit in the product of (526)289 x (1250)40

(a) 0 (b) 1 (c) 2 (d) 3

Solution.
(---6)289 = 6 , (---0)40 = 0

6 x 0 = 0
Solution

Q4. Find the roots of the equation.
√4y + 1 = √2y - 1

(a) 1 (b) 2 (c) both (d) no root exists

Solution.
(d) no root exists

squaring both sides 4y + 1 = 2y - 1

4y - 1 = -1-1

2y = -2

y = -1
Solution

Q5. Evaluate (18)3 - (10)3 - (8)3

(a) 4320 (b) 1000 (c) 2960 (d) 4831

Solution.
Note : a3 + b3 + c3 = 3abc
a + b + c = 0
= 3 x 18 x 10 x 8
= 4320
Solution

Q6. LCM and HCF of two numbers are 84 and 21 respectively and the ratio of two numbers are 1:4 . find the smallest number.

(a) 84 (b) 19 (c) 21 (d) 41

Solution.
HCF divides both the numbers exactly = 1 x 21 = 21
Solution

Q7. A fraction whose numerator is equal to or greater than the denominator is called improper fraction.

(a) yes (b) no (c) can't say

Solution.
(a) yes
Solution

Q8. The (2/10)th of square of a number is 20, find cube of the number.

(a) 10000 (b) 100 (c) 1000 (d) 10

Solution.
(2/10)x2 = 20

x2 = 100

x = 10
Solution

Q9. Find x .
(x + 3) log 3 = 2log 9

(a) 2 (b) 1 (c) 3 (d) 4

Solution.
log 3(x + 3) = log 92

log 3(x + 3) = log 34

x + 3 = 4

x = 1
Solution

Q10. Find x .
log(x2 - 3) = 0

(a) 5 (b) 4 (c) 2 (d) 1

Solution.
log(x2 - 3) = log 1

x2 - 3 = 1

x2 = 4

x = 2

x = 2
Solution