Q1.
Which statement is true for poisson distribution .
(a) It is uniparametric distribution .
(b) It could be unimodal or binomial
(c) Both
(d) None
Solution.
(c) Both
Solution
Q2.
In poisson distribution , if mean is 2, find V(x) .
Solution
V(x) = 2
because in poisson distribution E(x) = V(x)
Solution
Q3.
Poisson distribution is
(a) Negatively skewness
(b) Positively skewness
(c) Symmetric
(d) None of these
Solution.
(b) Positively skewness
Solution
Q4.
In poisson distribution if m = 4.8 , poisson distribution is
(a) unimodal (b) bimodal (c) both
(d) none
Solution.
(a) unimodal
Note : m = 4.8 (this is non - integer , so mode is 4, heigher included integer).
Solution
Q5.
In Poisson distribution , m = 6 poisson distribution distribution is
(a) unimodal (b) bimodal (c) both
(d) none
Solution.
(b) bimodal
m = 6 is an integer so there are two modes 6 and 5 (m and m - 1), that is why distribution is bimodal .
Solution
Q6.
If x ∿ P (m1) and y ∿ P (m2) then the distribution of random variable z = x + y will follow
poisson distribution with parameter .
(a) m1 + m2 (b) m1 - m2
(c) m1 . m2 (d) m1/m2
Solution.
m1 + m2
Solution
Q7.
In poisson distribution nP is
(a) Integer (b) Non- integer (c) Finite (d) Infinite
Solution.
(c) Finite
Solution
Q8.
As past experience the expected number of defectives are 2 out of 100, find V(x), if it follows poisson distribution .
Solution.
mean = E(x) =
2/100
= 0.02
So V(x) = 0.02 , As we know that in poisson distribution E(x) = V(x)
Solution
Q9.
The probability of at least one failure is the complement of the probability of ______ failure .
(a) zero failure (b) 2 failure (c) none (d) can't say
Solution.
(a) zero failure
P(x ≥ 1) = 1 - P(x = 0).
Solution
Q10.
Which distribution is uniparametric discrete distribution .
(a) Normal (b) Binomial (c) Poisson (d) None of these
Solution.
(c) Poisson
Solution
