Q1.
Which of the following is not a two dimensional diagram ?
(a) Rectangular diagram (b) Piechart (c) Line diagram
(d) Square diagram
Solution.
(c) Line diagram
Solution
Q2.
Find the value of x.
(
2/ 3
)3
. (2/ 3
)-6
= (2/ 3
)2x-1
(a) 2 (b) -1 (c) -2 (d) 8
Solution.
(
2/ 3
)
-3
= (
2/ 3
)
2x-1
-3 = 2x - 1
-2 = 2x
x = -1
Solution
Q3.
a:b = 3:4, b:c = 8:9 , a:c =
(a) 3:1 (b) 2:5 (c) 2:3 (d) 2:1
Solution.
3 x 8 : 4 x 9 = 24 : 36 = 2 : 3
Solution
Q4.
The sum of n terms of two A.P are in the ratio (4n + 7) : (2n + 9), find the ratio of their 15th term :
(a) 123:67 (b) 111:60 (c) 67:40 (d) 141:91
Solution.
Sn/Sn'
=
4n + 7/2n + 9
2a1 + (n-1)d1/2a2 + (n-1)d2
=
4n + 7/2n + 9
2a1 + [(n-1)/2]d1/2a2 + [(n-1)/2]d2
=
4n + 7/2n + 9
n - 1/2
= 2
n = 29
=
4(29) + 7/2(29) + 9
=
116 + 7/58 + 9
=
123/67
Solution
Q5.
x,y,z start a partnership firm. A contribute 1/3 of the capital for 1/5 of the time, B contribute 1/5 of the capital for 2/3 time, C contribute
rest capital for the whole time . find their profit ratio ?
(a) 4:7:9 (b) 3:6:4 (c) 2:1:4 (d) 1:2:7
Solution.
A's share : B's share : C's share
= 1/3 x 1/5 : 1/5 x 2/3 :[1 - (1/3 + 1/5)] x 1
= 1/15 : 2/15 : 7/15
= 1 : 2 : 7
Solution
Q6.
A sum was put at SI at a certain rate for 2 years. Had it been put at 2% higher rate , it would have fetched Rs 300 more , find the
sum .
(a) 10000 (b) 9000 (c) 7500 (d) 8500 `
Solution.
Sum =
More interest x 100 /Time x more rate
=
300 x 100 /2 x 2
=
30000 /4
= 7500
Solution
Q7.
If ax = b and by = a, find 2(xy)2.
(a) 1 (b) 2 (c) 7 (d) 8
Solution.
(b) 2
Solution
Q8.
In a quadratic equation x2 + px + q = 0 , (2 - √3) is a root of this equation find the value of p and q.
(a) (3,2) (b) (4,1) (c) (2,3) (d) (-4,1)
Solution.
(d) (-4,1)
Solution
Q9.
Find the average of all odd number upto 100.
(a) 80 (b) 70 (c) 50 (d) 60
Solution.
Formula =
n + 1/2
n = odd number
= 1,3,5,7,-----------99
=
99 + 1/2
=
100/2
= 50
Solution
Q10.
If a, b and c are consecutive number so find the value of log(ac + 1)
(a) 1 (b) 2 (c) 1og b (d) 2 log b
Solution.
a, b, c
a = b - 1 , c = b + 1,
log{(b - 1)(b + 1) + 1} = log(b2 - 1 + 1)
= log b2 = 2log b
Solution
