Measurement of Central Tendency
Question
Q1.
Mode can be calculated graphically
(a) Histogram (b) Ogive curve (c) Frequency polygon (d) Frequency curve
Solution.
(a) Histogram
Solution
Q2.
There are two groups having 13 and 12 observations with H.M. 130 and 120 respectively. Find the combined H.M.
Solution.
formula of combined H.M.=n1/(n1/H1) + n2/(n2/H2)
=13/(13/130) + 12/(12/120)
125
Solution
Q3.
Which averages are known as ratio averages :-
Solution.
H.M and G.M
Solution
Q4.
In a data there are 60 observations and each observations = 45 , then what will be the value of geometric mean.
Solution.
45
Solution
Q5.
Measurement of central tendency has impact of
(a) Change of scale (b) Change of origin (c) both (d) None of these
Solution.
(c) bOth
Solution
Q6.
If two variables x and y has relation x - y - 3 = 0 . Mode of x is 30 , what will be the mode of y .
Solution.
27
Solution
Q7.
If x and y are two variables, having relation 2x + 3y = 30 and mode of x is 5, find the mode of y.
Solution.
3y = 30 - 2x
y =
30 - 2x/3
=
30 - 10/3
=
20/3
Solution
Q8.
Quartiles can be determined graphically using .
Solution.
Ogive curve (or Cumulative frequency curve) .
Solution
Q9.
The A.M of two numbers is 20 and G.M is 16 then what will these two numbers .
Solution.
Let a and b are two numbers
A.M = (a + b)/2 , G.M = √ab
a = 32 , or 8
b = 8 or 32 .
Note : Using options one can solve these type of questions .
Solution
Q10.
Which result holds for a set of distinct positive observations, among AM, GM and HM ?
Solution.
A.M > G.M > H.M
Note : If all the observations are equal then A.M = G.M = H.M
Solution
