Alphabet Series
Q1.
Find next term : ABC , DEF , GHI , JKL
(a) ABO
(b) MNO
(c) RSU
(d) XYA
Solution. b
Pattern is 3 consecutive terms , So answer is MNO .
Solution
Q2.
Find next term :
BOS , DNT , FMU , HLV ________ .
(a) ABD
(b) JKW
(c) FMN
(d) XYZ
Solution. b
Pattern : first letter move two steps forward , middle term moves backwards one step and last letter move forward one step .
Solution
Q3.
Find next term :
BCB , DED , FGF , HIH , _____
(a) OKO
(b) JKJ
(c) NJN
(d) QSQ
Solution. b
Pattern : each letter move by + 2 .
Solution
Q4.
Find next term :
B,C E,G,K ________ .
(a) N
(b) M
(c) O
(d) P
Solution. b
Pattern : letters belong to prime number position .
Solution
Q5.
Find next term :
XMA , VNC , TOE , RPG _______ .
(a) PQI
(b) SQJ
(c) PMN
(d) OPQ
Solution. a
Pattern : first letter = -2 , second letter = +1 and third letter + 2 .
Solution
Q6.
_ bca _ c _ bca _ c _ bc
(a) ababa
(b) aabba
(c) aaabb
(d) None of these
Solution. a
ababa
In this case pattern will be abcabcabcabcabc
Solution
Q7.
aa _ _ cc _ _ bbc _
(a) bbbbb
(b) bbaac
(c)bbbcc
(d) None of these
Solution. b
bbaac
In this case pattern is aabbccaabbcc .
Solution
Q8.
a _ ca _ bc _ ab _ _
(a) babcc
(b) ababa
(c) bbbcc
(d) None of these
Solution. a
babcc
In this case pattern is abcaabcbabcc
Solution
Q9.
a _ a _ bb _ c _ aa _ b _ bccc
(a) ababab
(b) ccaabb
(c) abccab
(d) None of these
Solution.c
abccab
In this case pattern is aaabbbcccaaabbbccc
Solution
Q10.
_ Q _ PQR _ Q _ PQR _ Q _ .
(a) PRPRPR
(b) PQRPQR
(c) PPRRQQ
(d) None of these
Solution. a
PRPRPR
In this case pattern is PRQPRQPRQPRQPRQ
Solution
Q11.
4 x 9 = 5
16 x 25 = 9
36 x 49 =
(a) 13
(b) 12
(c) 14
(d) 15
Solution. a
Pattern (2)2 x (3)2 = 2 + 3 = 5
(4)2 x (5)2 = 9
(6)2 x (7)2 = 13 .
Solution
Q12.
12 x 11 = 0
14 x 21 = 14
16 x 31 = 32
18 x 41 =
(a) 64
(b) 54
(c) 45
(d) 41
Solution. b
12 x 11 = 12 x (1 - 1) = 0
14 x 21 = 14 x (2 - 1) = 14
16 x (3 - 1) = 32
18 x (4 - 1) = 54
Solution
Q13.
32 x 4 = 8
40 x 10 = 4
9 x 3 = 3
100 x 25 = ____ .
(a) 4
(b) 5
(c) 6
(d) 7
Solution. a
x = ÷ (Divide all) .
Solution
Q14.
9 x 2 = 36
15 x 1 = 30
80 x 4 = 640
15 x 10 = ________ .
(a) 300
(b) 200
(c) 100
(d) 50
Solution. a
Pattern :
9 x 2 = 18 x 2 = 6
15 x 1 = 15 x 2 = 30
80 x 4 = 320 x 2 = 640
15 x 10 = 150 x 2 = 300 .
Solution
Q15.
In a certain code word, if the word PLAYER is coded as AELPRY, then one can code the word VIGYAN .
(a) AGINVY
(b) AGYUNI
(c) IGUYAN
(d) none
Solution. a
In this case, letters are arrange in increasing order of their position in alphabets .
AGINVY
Solution
Q16.
In a certain code language , if 894563 is coded as ROCKET then how one can code 836453 .
(a) KETTOC
(b) RTECKT
(c) TRECKT
(d) None
Solution. b
It is very simple
8 → R
9 → O
4 → C
5 → K
6 → E
3 → T
So, 836453 → RTECKT
Solution
Q17.
If CRICKET is coded as TEKCIRC how one can code EXHIBIT .
(a) BITIEXH
(b) EXHIIBT
(c) TIBIHEX
(d) None
Solution. c
Reverse last three letter middle letter as it is, then reverse first three letters.
TIBIHEX
Solution
Q18.
If COMPAY can be coded as DQPTFG How one can code VISIT .
(a) WKVMX
(b) VTSII
(c) SITVI
(d) None
Solution. a
WKVMX
Inverse next alphabet by 1 .
Solution
